Algebra Lineal Howard Anton 5ta Edicion - Solucionario Introduccion Al

Una base para el subespacio es:

Solución:

Solución:

(1, -1)

| 2 0 | | 0 1 |

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Una base para el subespacio es:

Solución:

Solución:

(1, -1)

| 2 0 | | 0 1 |

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