Osnove Elektrotehnike 1 Srednja Skola Pdf -

( P = U^2 / R = 220^2 / 20 = 48400 / 20 = 2420 , \textW = 2.42 , \textkW ) Zadatak 3 (Redna veza) Dva otpornika od 10Ω i 20Ω vezana su redno na napon 30V. Izračunaj ukupni otpor, struju i pad napona na svakom.

Napon na svakom otporniku različit je i proporcionalan otporu. 6.2. Paralelna veza Svi otpornici su spojeni između iste dvije tačke. Isti napon je na svima.

[ R_u = R_1 + R_2 + R_3 + \dots ]

( I = U / R = 9 / 47 = 0.191 , \textA = 191 , \textmA ) Zadatak 2 (Snaga) Koliku snagu troši bojler od 220V ako mu je otpor 20Ω?

Kroz manji otpor teče veća struja. 6.3. Primjer kombinovanog kola U PDF-ovima se uvijek nalaze zadaci gdje treba izračunati ukupni otpor složenog kola (redno-paralelna mreža). 7. Kirhofovi zakoni Za rješavanje složenijih kola (koja nisu samo redna ili paralelna) koriste se Kirhofovi zakoni. 7.1. Prvi Kirhofov zakon (Zakon o čvorovima) Zbir struja koje ulaze u čvor jednak je zbiru struja koje izlaze iz čvora.

[ W = U \cdot I \cdot t ] Jedinica: . Praktična jedinica: Kilovat-čas (kWh) – ( 1 , \textkWh = 3.6 \times 10^6 , \textJ ). 5.2. Električna snaga (P) Snaga je rad u jedinici vremena. To je "brzina" kojom se troši energija.

[ R_u = \fracR_1 \cdot R_2R_1 + R_2 ]

[ I_ul = I_iz ] ili [ \sum I = 0 ] Zbir svih napona u zatvorenoj konturi jednak je nuli.

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