All rules satisfied. Use this to check your work, but more importantly, study the deduction steps above so you can replicate them under exam conditions. Game 2 of Games 42 Fr is a masterclass in relative ordering and block constraints. By methodically applying each rule, testing edge cases, and avoiding the common misreading of positional limits, you can solve it in under 3 minutes. Practice with similar games, and you’ll find that the same logical patterns reappear throughout the series.

| Position | 1 | 2 | 3 | 4 | 5 | 6 | 7 | |----------|---|---|---|---|---|---|---| | Element | G | F | A | C | D | E | B |

2: F 3: G 4: A 5: C 6: D 7: B

1 – 2 – 3 – 4 – 5 – 6 – 7 Element: E – A – C – D – B – F – G

If E cannot be in position 2 or 6 (adjacent to ends), then E can be in 1,3,4,5,7. Our last arrangement has E=1 → allowed. Then F(2)-G(3) have zero spaces? No – they are adjacent. Rule 4 says exactly one between → so F and G must be like F _ G or G _ F. Positions 2 and 3 are adjacent → violation.